求二维数组的最大子数组和

实验思路：

通过键入二维数组的信息构建二维数组，求出数组所有二位子数组的和并求出最大值

实验代码：

package er_wei_shu_zu;

import java.util.Scanner;

public class rwsz {
    static Scanner scanner = new Scanner(System.in);
    public static void main(String args[]){
        int m,n;
        int x;
        Scanner scanner = new Scanner(System.in);
       System.out.println("二维数组的列数：");
       m = scanner.nextInt();
       System.out.println("二维数组的行数：");
     n = scanner.nextInt();
      int arr[][] = new int[n][m];
      System.out.println("请逐行输入二位数组：");
       for(int i = 0;i<n;i++)
       for(int j=0;j<m;j++)
       {
           arr[i][j] = scanner.nextInt();
       }
       System.out.println("\n");
       x = maxArrSum(arr);
       System.out.println("该二维数组最大子数组的和为\n"+x);
   }
 
   //遍历所有二维数组的矩形区域
   
   static int  maxArrSum(int arr[][]){
       int m = arr.length;
       int n = arr[0].length;
       int p[][] = arrSum(arr);
       int ans = Integer.MIN_VALUE;
       for(int i=1; i<=m; i++){
           for(int j=1; j<=n; j++){
               for(int endi=i; endi <=m; endi++){
               for(int endj=j; endj<=n; endj++){    
                       int sum = p[endi][endj] - p[i-1][endj] - p[endi][j-1] + p[i-1][j-1];
                       if(ans < sum) ans = sum;    
                   }
               }    
           }    
       }    
       return ans;    
   }
   
   public static int[][] arrSum(int arr[][]){
          int m = arr.length;
           int n = arr[0].length;
           int p[][] = new int[m+1][n+1];
           p[0][0] = arr[0][0];
           for(int i=0; i<=m; i++) p[i][0] = 0;
           for(int i=0; i<=n; i++) p[0][i] = 0;
           for(int i=1; i<=m; i++){
               for(int j=1; j<=n; j++){
                   p[i][j] = p[i-1][j] + p[i][j-1] + arr[i-1][j-1] - p[i-1][j-1];
               }
           }
           return p;
       }
}

实验截图：